Mathématiques

Question

A= (5x+2)(3+4x)+(2x+3)(6x+2). B =(3z+1)(2z-1)+(7z+2)(3z-4). C=(2n-3) (6n-4) -(3n-2)(5-2n). D=(4-6y)(-3+6y-(6y+3)(-3-8y). besoin d'aide svp merci​

2 Réponse

  • Réponse :

    A = (5x+2)(3+4x)+(2x+3)(6x+2) = 15x + 20x² + 6 + 8x + 12x² + 4x + 18x + 6 = 27x² 45x + 12

    B = (3z+1)(2z-1)+(7z+2)(3z-4) = 6z² - 3z + 2z - 1 + 21z² - 28z + 6z - 8 = 27z²-23z- 9

    C = (2n-3)(6n-4)-(3n-2)(5-2n) = 12n² - 8n - 18n + 12 - 15n + 6n² + 10 - 4n = 18n²- 45n + 22

    D = (4-6y)(-3+6y)-(6y+3)(-3-8y) = -12 + 24y + 18y - 36y² + 18y+ 48y² + 9 + 24y = 12y² + 84y - 3

    Explications étape par étape

  • Réponse :

    salut

    Explications étape par étape

    A = (5x+2)(3+4x)+(2x+3)(6x+2)

    A= 15x+20x²  +6+8x+(2x+3)(6x+2)

    A= 23x+20x² +6+(2x+3)(6x+2)

    A= 23x+20x²  +6+12x²   +4x+18x+6  

    A= 23x+20x²  +6+12x²  +22x+6

    A= 23x+32x²   +6+22x+6

    A= 45x+32x²   +6+6

    A=45x+32x²   +12

    B=(3z+1)(2z−1)+(7z+2)(3z−4).

    B=6z²  −3z+2z−1+(7z+2)(3z−4)

    B=6z²   −z−1+(7z+2)(3z−4)

    B=6z²  −z−1+21z²    −28z+6z−8

    B=6z²   −z−1+21z²  −22z−8

    B=27z²  −z−1−22z−8

    B=27z² −23z−1−8

    B=27z²   −23z−9

    C=(2n−3)(6n−4)−(3n−2)(5−2n

    C=12n²    −8n−18n+12−(3n−2)(5−2n)

    C=12n²  −26n+12−(3n−2)(5−2n)

    C=12n²   −26n+12−(15n−6n  ²−10+4n)

    C=12n²  −26n+12−(19n−6n²   −10)

    C=12n²  −26n+12−19n+6n²  −(−10)

    C=12n²  −26n+12−19n+6n²  +10

    C=12n²  −45n+12+6n² +10

    C=18n² −45n+12+10

    D=(4−6y)(−3+6y−(6y+3)(−3−8y)

    D=(4−6y)(−3+6y−(−18y−48y y  ²−9−24y))

    D=(4−6y)(−3+6y−(−42y−48y y ²   −9))

    D=24+192y+192y y²  −36y−288y y²  −288y y³

    D=  24+156y−96y y²   −288y y ³

Autres questions